[Python-au] output of dis.dis(lambda x: x)

[Pete Ryland]

On 19/04/07, Andrew McNamara <andrewm at object-craft.com.au> wrote:
> Not really - I'd just suggest wrapping it in a function and using a
> try/finally block like this:
>
>     def dis_str(code):
>         out = cStringIO.StringIO()
>         old_stdout = sys.stdout
>         try:
>             sys.stdout = out
>             dis.dis(code)
>         finally:
>             sys.stdout = old_stdout
>         return out.getvalue()

Perhaps worth doing:

def dis_str(*args, **kargs):
  ...
  dis.dis(*args, **kargs)
  ...

Pete